Question

the multiplicative inverse of (2+3i)^2

Answer 1

Answer:

(2+4i)^2 is2+2+3(4(4+5+--(&&&578855

Step-by-step explanation:

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Answer 2

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The multiplicative inverse of (2+3i)^2 is=$\displaystyle\frac {1}{({2+3i })^{2}}$