Question

The multiplicative inverse of 2-3i is?​

Answer 1

Answer:

Step-by-step explanation:

$\frac{1}{2-3i} \\=\frac{1}{2-3i}*\frac{2+3i}{2+3i}\\\\=\frac{2+3i}{2^2-(3i)^2}\\\\=\frac{2+3i}{4-(-9)}=\frac{2+3i}{13}$

I hope you were referring to i=√(-1)

Hope it helps!

<3