Question

the multiplocity of a zero 7, in the function f(x) = (x-7)^5 + (x+4)³​

Answer 1

Given :   function f(x) = (x-7)⁵ (x+4)³​

To find : multiplicity of a zero 7

Solution:

f(x) = (x-7)⁵ (x+4)³​  

Zeroes are 7  & - 4

(x-7)⁵

= (x -7)(x-7)(x-7)(x-7)(x-7)(x-7)

Hence 7 factor is coming 5 times

Hence multiplicity of zero 7 is 5

(x+4)³​   = (x + 4)(x +4)(x + 4)

Hence multiplicity of zero -4 is 3

multiplicity of zero 7 is 5

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