Question

the must valuw of 5k=3, k2, 3k=11 will form are an arithmetic sequence? Show solution and answer.

Answer 1

Hey There,

# Correct question would be as follows -

Q. What must be the value of k so that 5k-3, k+2, and 3k-11 will form an arithmetic sequence ?

◆ Answer -

k = 3

● Explaination -

Let's consider 5k-3, k+2 and 3k-11 form an AP with common difference d.

t1 = 5k - 3

t2 = k + 2

t3 = 3k - 11

Common difference in an AP is calculated as -

d = t2 - t1 = t3 - t2

(k + 2) - (5k - 3) = (3k - 11) - (k + 2)

k - 5k - 3k + k = -11 - 2 - 2 - 3

-6k = -18

k = 3

Therefore, value of k must be 3 so that 5k-3, k+2 and 3k-11 form an AP.

Thanks dear..