Physics, asked by abhirom06, 9 months ago

The muzzle velocity of a 50.0 g shell leaving a 3.00 kg rifle is 400 m/s.

What is the recoil velocity of the rifle?​

Answers

Answered by Kumar7088
1

Answer:

Explanation:

Horizontal momentum will be conserved because there is no external horizontal force on the body so that

m1.v1=m2.v2

3×v=0.05×400

V=20/3

Answered by xdig6969
0

Answer:

v= 6.66m/s

Explanation:

m*v=m*v

(3kg)(v)=(0.05)(400)

3v=30

3v/3=30/3

v= 6.66m/s

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