Question

The n and I quantum numbers of the last electon of an element are n=5 and 1=2. The elements is?​

Answer 1

$\huge{\underline{\bold{\red{Answer :-}}}}$

l=1 for p subshell and n=4

⟹ 4p

It can accomodate 6 electrons. So a total of 6 different elements can have the last electron with quantum numbers n=4 and l=1

Answer 2

Answer:

l = 1 for p subshell and n = 4

⟹ 4p

It can accomodate 6 electrons.

So a total of 6 different elements can have the last electron with quantum numbers n = 4 and l = 1