Question

The ‘ n’ of CBr3 molecule is 2.Then what is the molecular formula
1. CBr6
2. C2Br3
3. C2Br6
4. C3Br6​

Answer 1

Answer:

answer is (c) option C2Br6

Explanation:

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Answer 2

The ‘n’ of $\[CB{r_3}\]$ molecule is 2. Then, the molecular formula is $\[{C_2}B{r_6}\]$. Thus, the correct option is 2.

Explanation:

• The relation between molecular formula and the empirical formula is $\[Molecular\,formula = n \times Empirical\,formula\]$

• As the value 'n' is 2, the molecular formula will be $\[Molecular\,formula = 2 \times CB{r_3} = {C_2}B{r_6}\]$

• Thus, the molecular formula of the compound is $\[{C_2}B{r_6}\]$.