the n term of an ap is 5n-2 find (1)the Ap (2) 61st term of ap (3) sum of first 25 terms of ap
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Step-by-step explanation:
an = 5n-2
a1 = 5(1) - 2=3
a2 = 5(2) - 2=8
a3 = 5(3)-2 = 13
d = a2-a1=8-3=5
(1)AP=3,8,13
(2) a63 = a+(n-1)d
= 3+63*5
a63 =318
(3) s25 = n(2a+(n-1)d)/2
25(6+24*5)/2
25(126)/2
1575
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