Question

The n th term of an AP is 6n+2 .find its common difference

Answer 1

an=6n+2

n=1,2,3

a1=6×1+2=8

a2=6×2+2=14

a3=6×3+2=20

Therefore AP=8,14,20

d=a2-a1

d=14-8

d=6

Answer 2

Answer:

$Common\: difference\:in \:given \\A.P = 6$

Step-by-step explanation:

$Given \\ n^{th} \: term\:of\:an\:A.P =a_{n}=6n+2$

$Now,\\common\: difference (d)=a_{n}-a_{n-1}$

$=(6n+2)-[6(n-1)+2]$

$=6n+2-(6n-6+2)\\=6n+2-(6n-4)\\=6n+2-6n+4\\=6$

Therefore,

$Common\: difference\:in \:given \\A.P = 6$

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