The n th trem of an arithmetic progression is given by a n a = 3 n - 2 then the 12 th trem is
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Answer:
an = 3n + 2 Given sequence whose an = 3n + 2 To get the first five terms of given sequence, put n = 1, 2, 3, 4, 5 and we get a1 = (3 × 1) + 2 = 3 + 2 = 5 a2 = (3 × 2) + 2 = 6 + 2 = 8 a3 = (3 × 3) + 2 = 9 + 2 = 11 a4 = (3 × 4) + 2 = 12 + 2 = 14 a5 = (3 × 5) + 2 = 15 + 2 = 17 ∴ The required first five terms of the sequence whose nth term, an = 3n + 2 are 5, 8, 11, 14, 17.Read more on Sarthaks.com - https://www.sarthaks.com/651463/write-the-first-terms-of-the-sequences-whose-nthterm-are-an-3n-2
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Answer:
34
Step-by-step explanation:
n=3x12-2
=36-2
=34
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