The Na+ and Cl- ions which initially at certain distance apart starts moving
towards each other due to mutual attraction. As they approach each other, their
centre of mass is
1) Shifts near to CI-
2) Shifts near to Na+
3) Remains in same position
4) always at the mid point Na+ & Cl-
Answers
Answer: In the fcc unit cell of NaCl, along a given edge, chloride ions present at corner sodium ion present at edge centre touch each other.
Hence, the edge length a=2r
= Na + +2r Cl −
=2(r Na + +r Cl−)
Here, (r Na+ +r Cl −) is the distance between sodium and chloride ions.
The length of the edge of the unit cell is twice the distance between sodium and chloride ions in sodium chloride crystal. It is 2X
Explanation: pls mark me brainliest
Answer: Centre of mass of the ions remains at same position.
Explanation:
The Na⁺ and Cl⁻ ions are moving under their mutual attractive force.
If we take Na⁺ and Cl⁻ as a system, there is no external force acting on the system.
The mutual attractive force becomes an internal force.
Initially both ions were at rest, therefore, the centre of mass was at rest.
As there is no external force and initial velocity of centre of mass is zero, the centre of mass will remain at rest at all time.
Hence, the centre of mass of our system , i.e. , Na⁺ and Cl⁻ ions will remain at same position.
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