Question

The National Service Scheme (NSS) is an Indian government-sponsored public service program that aimed at developing student’s personality through community service. The volunteers of NSS erected a conical tent made of tarpaulin in a flood affected area. If vertical height and diameter of the conical tent are 3m and 8m, respectively and the width of tarpaulin is 250cm, then answer the following.
(i). What is the area of the tarpaulin used?
(ii). What is the length of the tarpaulin used, if 10% extra material is required for stitching margin and wastage ? (Take =3.142)​

Answer 1

Step-by-step explanation:

i) l²= r²+h²

l = √25

l = 5

now We will take C.S.A of conical tent

= 3.14 × 4 × 5

= 62.8

Answer 2

Answer:

(i)   The area of the tarpaulin is $62.84 m^2$

(ii) The length of the tarpaulin used is 15710 cm.

Step-by-step explanation:

(i) To find the area of the tarpaulin used for the conical tent, we can use the formula for the lateral surface area of a cone:

A = π * r * l

where r is the radius of the base of the cone (half of the diameter) and l is the slant height of the cone.

The radius of the base of the cone is ($8/2$) = 4m.

To find the slant height, we can use the Pythagorean theorem:

$l^2 = h^2 + r^2$ (h is the height and r is the radius)

$l =$ $sqrt(3^2 + 4^2)$$= sqrt(9 + 16)$$= sqrt(25)$$= 5m$

Now we can substitute these values into the formula to find the area of the tarpaulin:

A = π $* 4 * 5$ = 20π $m^2$= $20*3.142$ = $62.84 m^2$

(ii) The length of the tarpaulin used can be found by multiplying the area of the tarpaulin by the width of the tarpaulin:

L = $62.84 * 250 *10/100$$= 15710 cm$

10% extra material is required for stitching margin and wastage.

So, the length of the tarpaulin used is 15710 cm.

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