the native silver forms a water soluble compound b with dilute aqueous solution of NACN in the presence of a gas a the Silver metal is obtained by the addiction of a metal c to B and complex d is a formed as a by product write the structure of c and d and identify A and B in the following sequence= AG + NaCn +(A )+ H2O -----> (b) +OH + na+(c) +(b) ---->(d) +ag
Answers
Explanation:
The native silver reacted with dilute aqueous solution of NaCN in the presence of gas oxgen gas to form Na[Ag(CN)2] which is a water soluble compound.
The silver metal is obtained by the addition of Zinc metal to Na[Ag(CN)2] and complex Na2[Zn(CN)4] is formed formed as by product. Therefore the correct sequence is
Ag + NaCl + O2 + H2O Na[Ag(CN)2] + OH- + Na + (Zn) + Na[Ag(CN)2] + Na2[Zn(CN)4] + Ag
Hence
A = O2
B = Na[Ag(CN)2]
C = Zn
D = Na2[Zn(CN)4]
Answer:
The native silver forms a water soluble compound (B) with dilute aqueous solution of NaCN in the presence of a gas (A). The silver metal is obtained by the addition of a metal (C) to (B) and complex (D) is formed as a byproduct. Write the structures of (C) and (D) and identify (A) and (B) in the following sequence : Ag + NaCN + [A] + H2O [B] + OH- + Na+ [C] + [B][D] + AgRead more on Sarthaks.com - https://www.sarthaks.com/15796/native-silver-forms-water-soluble-compound-with-dilute-aqueous-solution-nacn-presence-gas