Question

The natural isotopic abundance of 10B is 19.60% and 11B 80.40 %. The exact isotopic masses are 10.13 and 11.009 respectively. Calculate the average atomic mass of boron

Answer 1

Answer:

10.84

Explanation:

To tackle this question we must first understand that the abundances must add up to 100%

So to find the average atomic mass of boron we divide the abundances given by 100% then  we multiply with the isotopic masses

Let us start with 10B

19.60 ÷ 100% = 0.1960 %

0.1960 × 10.13 = 1.9855

We then proceed to11B

80.40 ÷ 100% =0.804%

0.804 × 11.009 = 8.851

We the add what we have found from 10B and 11B

1.9855 + 8.851 = 10.84

Answer 2

Explanation:

here's your answer

10.84

hope you GET it