The natural uranium consists of three isotopes in the ratio 99.274 : 0.720 : 0.006. Find the average atomic mass of uranium
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Answer:
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Explanation:
Answer
Correct option is
A
86
Activity(A)=
half life ln2
×Number of particles(N) −(1)
Given that for 92
U 234, 92
U 235 and 92
U 238 :
The number of particles are in ratio, 0.0006:0.71:99.28 and half-life are in ratio, 2.5:7100:45000
From the equation (1), the activities are in ratio: 2.4:1:22
So, percentage share in total activity of natural uranium are 9.45%, 3.94% and 86.61% for the
92
U 234 , 92
U 235 and 92
U 237.97 respectively.
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Answer:
The natural uranium consists of three isotopes in the ratio 99.274 : 0.720 : 0.006. Find the average atomic mass of uranium
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