Question

The nature of roots of (5s+3)(2s+1)=s2-s-1 is

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

Roots are equal and real.

Step-by-step explanation:

Given (5s+3)(2s+1)= s²-s-1

10s² + 5s + 6s +3 = s²-s-1

10s² + 5s + 6s +3-s²+s+1 = 0

9s²+12s+4 = 0

By comparing above equation from as²+bs+c = 0

So a = 9, b = 12, c = 4

∴ Discriminant D = b²-4ac

D = 12²-(4×9×4)

D = 144-144

D = 0

∵ Discriminant is zero, so both roots are equal and real.

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