Question

The nature of roots of quadratic equation x2-5x-7 = 0 are real and equal. true or false​

Answer 1

Answer:

false

they are real and distinct

Step-by-step explanation:

B^2-4AC

25-(4*(-7)*1)

25-(-28)

53

Answer 2

Answer:

$x^{2}-5x-7=0$

a = 1

b = -5

c = -7

to see whether it has real and equal roots D should be equal to 0

$D=b^{2}-4ac\\\\D=(-5)^{2}-4(1)(-7)\\\\D=25+28\\\\D=53$

∵ D ≠ 0

thus this equation will not have real & equal roots.

Hence the statement is false.