Physics, asked by shifatasneen13, 4 months ago

The nature of the image formed by concave
mirror when the object is plaud between the
focus (f)and center of curvature (c)of the mirror
observed by us is
a.Real, inverted & diminished
b.Virtual, erect & smaller in size
c.Real, inverted & enlarged
d. virtual,upright & enlarged.

Answers

Answered by MystícPhoeníx
111

Answer:-

\setlength{\unitlength}{1cm}\begin{picture} \linethickness\linethickness{0.22mm}\put(0,0){\line(1,0){10}}\put(5,0){\vector(0,1){1}}\put(1.5,0){\vector(0,-1){2.9}}\qbezier(6.5,3)(8,0)(6.5,-3)\linethickness{0.25mm}\put(5,1){\line(1,0){2.15}}\qbezier(7.15,1)(6,0)(0.5,-3.5)\qbezier(1,-3.5)(5,1)(6.5,2.85)\put(5.75,-0.11){$\bullet$}\put(4,-0.11){$\bullet$}\put(6,-0.5){\bf F}\put(3.7,0.3){\bf C}\put(4.8,-0.35){\bf A}\put(4.8,1.3){\bf B}\put(1.7,-3.4){\bf B'}\put(1.3,0.3){\bf A'}\put(7.5,-0.5){\bf P}\put(7.3,1){\bf D}\put(7,2){\bf E}\put(6,1){\vector(1,0){0}}\put(5.8,2){\vector(3,2){0}}\put(2.9, - 2){\vector( - 1, - 2){0}}\put(3.2,  - 1){\vector( - 1, - 2){0}}\end{picture}

The nature of the image formed by concave

mirror when the object is placed between the

focus (f)and center of curvature (c)of the mirror

observed by us is Real , Inverted & enlarged

Hence , Options (c) is the correct answer .

The image is formed between centre of Curvature and Infinity .

Additional Information !!

• Real Image :- The image that can be obtained on a screen is called Real Image

• Real Image is Inverted.

• It formed where light rays actually meet .

• Virtual Image :- The image that cannot be obtained on the screen are called Virtual Image.

• It formed when light rays appears to meet.

• Virtual Image is Erect.


prince5132: Good !!
nirman95: Hello, Please provide ray diagrams for these kind of questions, it makes the answer more clear to the students.
Answered by pinkybansal1101
1

Answer:

\setlength{\unitlength}</p><p></p><p>{1cm}\begin{picture} \linethickness\linethickness{0.22mm}\put(0,0l</p><p></p><p>{\line(1,0){10}}\put(5,0){\vector(0,1)</p><p></p><p>{1}}\put(1.5,0){\vector(0,-1) {2.9}}\qbezier(6.5,3)(8,0)</p><p></p><p>(6.5,-3) \linethickness{0.25mm}\put(5,1)</p><p></p><p>{\line(1,0){2.15}}\qbezier(7.15,1)(6,0) D}\put(7,2){\bf E}\put(6,1){\vector(1,0) {0}}\put(5.8,2){\vector(3,2){0}}\put(2.9,-2)</p><p></p><p>(0.5,-3.5)\qbezier(1,-3.5)(5,1)</p><p></p><p>(6.5,2.85)\put(5.75,-0.11)</p><p></p><p>{$\bullet$}\put(4,-0.11) {$\bullet$}\put(6,-0.5){\bf F}\put(3.7,0.3)</p><p></p><p>{\bf C}\put(4.8,-0.35){\bf A}\put(4.8,1.3) {\bf B}\put(1.7,-3.4){\bf B'}\put(1.3,0.3){\bf</p><p></p><p>A'}\put(7.5,-0.5){\bf P}\put(7.3,1){\bf</p><p></p><p>{\vector( - 1,-2){0}}\put(3.2, 1){\vector( - 1, - 2){0}}\end{picture}

When object is placed between focus(f) and Centre of curvature (C) then the image is formed beyond the centre of curvature .

The properties of such a image are

  • Real
  • Enlarged
  • Inverted

Thus (c) is the correct asnwer.

_________________

KNOWLEDGE EXPRESS

REAL IMAGE

A real image is formed when rays of light actually meet at a point . A real image is always inverted and can be obtained on the screen

VIRTUAL IMAGE

A virtual image is formed when rays do not actually meet at a point but appear to come from a certain point .It Is erect with respect to object and cannot be obtained on a screen

A concave lens can form both type of images

_________________

Mark as BRAINLIEST

@phenom

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