Question

. The nature of the root of the quadratic equation 8x2 - 7x + 1 = 0​

Answer 1

Answer:

The roots are real and distinct

Step-by-step explanation:

Comparing given quadratic equation $8x^2-7x+1=0$ with general quadratic equation $ax^2+bx+c=0$, we have $a=8,b=-7,c=1$

So discriminant  $=b^2-4ac$

                           $=(-7)^2-4(8)(1)\\=49-32\\=17>0$

Since discriminant is positive so roots are real and distinct