Question

The nature of the roots of 3k^2 -2k+1/3=0

Answer 1

Answer:

k=1/3 and the roots are real and equal.

Step-by-step explanation:

3k^2-2k+1/3=0

when we take the l.c.m as 3 we get

9k^2-6k+1=0

this can be written as

(3k-1)^2=0

so the roots are k=(1/3,1/3)

Hence the roots are real and equal.

Answer 2

Step-by-step explanation:

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