Question

the nature of the roots of a quadratic equation 2x^2-6x+3=0 is​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

2x^2 −6x+3=0

x= −(−6)±√ (−6) ^2 −4×3×2/2×2

⇒

x= 6±√ 12/4

∴ Real & irrational