Question

the nature of the roots of the equation 2 x square - 7 x + 10 equal to zero Hour​

Answer 1

Equation =

$2x^{2} - 7x + 10 = 0$

a= 2 ; b=-7 ; c = 10

D = b² - 4ac

= (-7)² - 4(2)(10)

= 49 - 80

= - 31

Since D<0 , no real roots exist (i.e) only imaginary roots exist.

Answer 2

The nature of the roots of the equation are imaginary.

Step-by-step explanation:

Given : Equation $2x^2-7x+10=0$

To find : The nature of the roots of the equation ?

Solution :

The nature of the roots of the equation is determined by discriminant.

1) If $D=b^2-4ac=0$ then roots are real and equal.

2) If $D=b^2-4ac>0$ then roots are real and unequal.

3) If $D=b^2-4ac<0$ then roots are imaginary.

In equation $2x^2-7x+10=0$,

Here, a=2, b=-7 and c=10

Substitute in discriminant,

$D=(-7)^2-4(2)(10)$

$D=49-80$

$D=-31$

$D<0$

Therefore, the roots are imaginary.

#Learn more

Find the values of K for which the rroots are real and equal in each of the following equation: 1)Kx(x-2)+6

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