Question

The nature of the roots of the quadratic equation 2x^2 - 2√3x - 3= () ​

Answer 1

Step-by-step explanation:

To find the nature of the roots, use

b²-4ac formula.

Here, a = 2, b = -2√3, c = -3

$b ^{2} - 4ac = ( { - 2 \sqrt{3} )}^{2} - 4 \times 2 \times ( - 3)$

$=12 + 24$

$= 36$

Here, b² - 4ac > 0

Therefore, nature of the roots is real and unequal