the near and far points of an woman are 30cm and 180cm find the power of lens she should use while reading at 25cm
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1/f=1/u - 1/v , where u is the near point of normal eye and v is the near point of defected eye.
1/f=1/25 - 1/30
1/f=(30-25)/30×25
So, f = 750/5=150 cm=1.5 m
P=1/f(in m)=1/1.5=2/3 D=0.67 D
PLZ MARK IT AS BRAINLIEST..
1/f=1/25 - 1/30
1/f=(30-25)/30×25
So, f = 750/5=150 cm=1.5 m
P=1/f(in m)=1/1.5=2/3 D=0.67 D
PLZ MARK IT AS BRAINLIEST..
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