the near point of a hypermetropic person is 75 cm calculate the focal length and power of the lens used in his spectacles
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⭐⭐⭐ phoenix ⭐⭐⭐
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1/v+1/u=1/f
u=-25cm
v=-75cm
(1/-75) -(1/-25) =2/75
Focal length =75/2
Power of lens 1/focal length =2/75
= 0.026D
Hope it will help you...
#phoenix
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Answer:1/v+1/u=1/f
u=-25cm
v=-75cm
(1/-75) -(1/-25) =2/75
Focal length =75/2
Power of lens 1/focal length =2/75
= 0.026D
Hope it will help yo
Explanation:
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