the near point of a person suffered from hypermetropia is at 50 cm from his eye what is the power of the lens needed to correct this defeat
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Heyy mate ❤✌✌❤
Here's your Answer...
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Convex Lens is suitable to correct the defect.
u = -25
v= -50
Therefore, by lens formula
1/-50+1/25=1/f
1/f=1/50
f=50cm
,p=1/0.5=100/50=2D
power=2 dioptre
✔✔✔
Here's your Answer...
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Convex Lens is suitable to correct the defect.
u = -25
v= -50
Therefore, by lens formula
1/-50+1/25=1/f
1/f=1/50
f=50cm
,p=1/0.5=100/50=2D
power=2 dioptre
✔✔✔
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