Question

the near point of hypermetropic eye of a person is 50 cm what is the power of lens is reduced to have normal vision​

Answer 1

Answer:

2 DIOPTRE

Explanation:

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Q. 8

5.0

( 3 Votes )

The near point of a person suffering from hypermetropia is at 50 cm from his eye. What is the nature and power of the lens needed to correct this defect? (Assume that the near point of the normal eye is 25 cm.)

Class 10th

Evergreen Science

11. The Human Eye and The Colourful World

Answer

According to the question

Object Distance (u) = -25 cm

Image Distance (v) = -50 cm

By Lens Formula

⇒

⇒

⇒ F = 50 cm.

Since focal length is positive hence the lens is convex lens.

Power =

Focal length = 50 cm = 0.5 m

1 m = 100 cm.

⇒ Power =

Hence the Power is 2 Dioptre