Question

The near point of the eye of a person is 50 cm. Find the nature and
the corrective lens required by the person to enable him to see clearly the
objects placed at 25 cm. from the eye.
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Answer 1

Answer:

u= -50

v= -25

f=?

1/f=1/v-1/u

=(1/-50)-(1/-25)

= (-1/50)+(1/25)

= -1+2/50

1/f = 1/50

f= 50

power= 100/50

=+2D

the lens used is convex lens