The near point of the hypermetropic eye is 60cm. what is the nature and power of lens required to enable him to read a book placed at 25 cm from the eye?
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convex lens of power 0.028 D
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Lens formula is given by 1/f = 1/u + 1/v
Here, f is the focal length
u is the distance at which object is placed from lens.
v is the distance of image from lens.
Given details:
v = -60
u = 25
1/f = 1/25 + 1/(-60)
1/f = 0.04 - 0.0167
1/f = 0.023 / cm
1/f = 2.3 / m
Power of lens is P = 1/f = 2.3 D
Since the power of lens is positive, nature of lens is convex.
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