Question

the nearest 1000 of 85654 is:_______​

Answer 1

Step-by-step explanation:

Answer

Verified answer

Let the number of prizes of money 100 be X, and the number of prizes of cost 25 be

y;

x+y = 63

y = 63-x

--(1)

100x+25y = 300 4x+y = 120 y = 120-4x (2)

63-x = 120-4x

4x-x = 120-63

3x = 57

x = 19

y = 63-x = 63-19

y = 44

Answer 2

Answer:

The nearest 1000 of 85654 is:

86000