the neck and bottom are 2cm and 10cm in diameter respectively if the cork is pressed with a force of 1.2kgf in the neck of the bottle. calculate the force exerted on the bottom of the bottle
Answers
Answered by
1
Answer:
Radius of the cork at the neck is 1cm.
Area of the cork, A
c
=π×1
2
cm
2
So, pressure applied through the cork, P
c
=
π×1
2
1.2
kgf.cm
−2
Same pressure is applied on the bottom of the bottle as per Pascal's law.
Radius of the bottom of bottle is 5cm.
Area of the bottom, A
b
=π×5
2
cm
2
So, force applied at the bottom = P
c
×A
b
=
π×1
2
1.2
×π×5
2
=1.2×25=30kgf
Answered by
1
Answer:
ok na understood
don't
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