The neck and bottom of a bottle have diameters 2cm and 8cm respectively. The bottle is completely filled with kerosine. If the cork in the neck is preseed with a force of 10N , what force is exerted on the bottom of the bottle
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Answer:
Radius of the cork at the neck is 1cm.
Area of the cork,
A
c
=
π×
2
1 2
So, pressure applied through the cork,
P
c
=
π×1
2
1.2
kgf.
cm
−2
Same pressure is applied on the bottom of the bottle as per Pascal's law.
Radius of the bottom of bottle is 5cm.
Area of the bottom,
A
b
=
π×
2
5 2
So, force applied at the bottom =
P
c
×
A
b
=
π×1
2
1.2
×
π×
5 2
1.2×
25=
30kgf
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