Question

The needle of a dip circle shows an apparent dip of 45° in a particular position and 53° when the circle is rotated through 90°. Find the true dip.

Answer 1

True Dip, $\delta$  is given by $\delta=38.6^{\circ} \approx 39^{\circ}$

Explanation:

Given data in the question:

Apparent dip shown by dip circle needle,  $\delta_{1}=45^{\circ}$

Dip shown by dip circle needle when the circle is rotated, $\delta_{2}=53^{\circ}$

True Dip,$\delta$  is given by the

$\cot ^{2} \delta=\cot ^{2} \delta_{1}+\cot ^{2} \delta_{2}$

$\cot ^{2} \delta=\cot ^{2} 45^{\circ}+\cot ^{2} 53^{\circ}$

$\cot ^{2} \delta=1.56$

      $\delta=38.6^{\circ} \approx 39^{\circ}$