the negation of (p → q)^r is
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Step-by-step explanation:
p→q
=∼p∨q−−−(1)
∼[(p→q)∧r]
∼[∼p∨q∧r]...[form(i)]
∼(∼p∨q)∨∼r...[Demorgans low]
∼(∼p)∧∼q∨q∼r av(b∧c)
p∧∼q∨∼r =(a∨b)∨(a∨c)]
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