Question

the negation of (p → q)^r is​

Answer 1

Step-by-step explanation:

p→q

=∼p∨q−−−(1)

∼[(p→q)∧r]

∼[∼p∨q∧r]...[form(i)]

∼(∼p∨q)∨∼r...[Demorgans low]

∼(∼p)∧∼q∨q∼r av(b∧c)

p∧∼q∨∼r =(a∨b)∨(a∨c)]