the negative of minus 2 upon 3 raise to power 3 is
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Solution:
Let (-2/3)³ should be divided
by x get the quotient (9/8)²
=> (-2/3)³ /x = (9/8)²
=> (-2/3)³ × (8/9)² = x
=> (-2³/3³)×(2³/3²)² = x
=> (-2³/3³)×(2^6/3⁴) = x
=> (-2³×2^6)/(3³×3⁴) = x
=> (-2^9)/3^7 = x
Therefore,
Required number (x) = (-2^9)/3^7
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