Physics, asked by vasu555vg, 8 months ago

The net electric flux due to the net charge enclosed by a surface is given by Ф= q/ E (Gauss Theorem) . The electric flux due to a unit charge is given by Φ= q/E . What encloses this charge according to Gauss theorem? Is the space around this free charge which encloses it a Gaussian surface? Can earth / surrounding be considered as a Gaussian surface enclosing this charge? What will be the flux if a unit positive charge is enclosed by earth and space and the charge is placed at the Earth's atmosphere? What will be the value of E in this case?. Justify your answer in detail.

Answers

Answered by rsultana331
1

Answer:

Electric Flux through a surface is defined as the surface integral of the electric field lines passing normally through the surface.

ϕ=∫

E

.

dS

According to gauss's law, total electric flux through a closed surface equals the net charge enclosed in the surface divided by the permittivitty.

Consider a point charge q. Its net electric flux through any closed surface enlcosing it will be be equal to ϕ=

ε

o

q

. This is independent of the choice of the shape and size of the closed surface.

The SI unit of electric flux is Volt - metres (V m)

(b)

For charged spherical shell, all charge lies on the outer circumference of the surface.

Consider a charged spherical shell with outer radius b and inner radius a. The charge resides at a radius b from the centre. Consider a gaussian surface of radius a<r<b. Charge enclosed in this guassian surface will be zero.

Using gauss's law,

∫E.ds=

ε

o

q

enclosed

E×2πrdr=0

E=

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