The net force for the following diagram 10n to right ,5n to right
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F
1
+F
2
)
max
=16N F
net
=
F
1
2
+F
2
1
+2F
1
F
2
cosθ
cosθ=+1(max)
(F
1
−F
2
)
min
=4N cosθ=−1(min)
As 2,3N are below min value they are not
possible.
As 17 N is greater then max possible value;
only 15 N is possible
1
+F
2
)
max
=16N F
net
=
F
1
2
+F
2
1
+2F
1
F
2
cosθ
cosθ=+1(max)
(F
1
−F
2
)
min
=4N cosθ=−1(min)
As 2,3N are below min value they are not
possible.
As 17 N is greater then max possible value;
only 15 N is possible
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