Question

the net force on a test mass mo in a gravitational field is the product of mo at that point and

​

Answer 1

Step-by-step explanation:

Assume a element of mass dm at a distance X from mass m

Force due to small element of rod dF=

X

2

Gdm×m

F=∫

a

a+l

X

2

Gdm×m

dm=

l

M

dx

F=∫

a

a+l

lX

2

GM×m

dx

F=

l

GM×m

[

X

1

]

a

a+l

F=

l

GM×m

[

a+l

1

−

a

1

]

a

a+l

F=

a(l+a)

GM×m

Answer 2

Answer:

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