Question

The net forces acting on 2 kg and 3 kg blocks respectively are
15 NO 3 kg
2 kg
smooth
15 NON
15 N. 15 N
15 N, 12 N
6 N9N​

Answer 1

Solution:-

First, find the acceleration of block

Method:- 1

$\rm : \implies \: \Sigma \: f_x = ma_x$

=> 15 = ( 2 + 3 ) a

=> 15 = 5a

=> a = 15/5

=> a = 3 m/s²

Method:- 2

$\boxed{ \rm \: a \: = \dfrac{net \: pushing \: force}{total \: mass} }$

$\rm \: = \dfrac{15}{2 + 3} = \dfrac{15}{5} = 3m/ {s}^{2}$

Now finding force

Note :- FBD of both the block are attached

Using :-

$\rm : \implies \: \Sigma \: f_x = ma_x$

For 2kg block

Using the formula:-

=> F = Ma

So we have

=>M = 2 kg

=> a = 3m/s²

=> F = 2 × 3

=> F = 6 N

This can also be solved as under

For 3kg block,

Using the formula:-

=> F = Ma

So we have

=>M = 3 kg

=> a = 3m/s²

=> F = 3 × 3

=> F = 9 N

So Force on 2 kg block is 6N and Force on 3kg block is 9N

Option D is correct