Question

The net of a square pyramid is shown: A square is shown having each side equal to 0.75 inch. Each side of the square has a triangle on it. The height of the triangle is labeled as 0.8 inch. What is the surface area of the figure? 0.5625 square inch 0.7625 square inch 1.5625 square inches 1.7625 square inches

Answer 1

Question :- The net of a square pyramid is shown: A square is shown having each side equal to 0.75 inch. Each side of the square has a triangle on it. The height of the triangle is labeled as 0.8 inch. What is the surface area of the figure ?

A) 0.5625 square inches .

B) 0.7625 square inches .

C) 1.5625 square inches .

D) 1.7625 square inches .

Solution :-

we know that,

• Area of a ∆ = (1/2) * Base * height .
• Area of square = (side)² .
• Surface area of a regular pyramid = Area of its lateral faces + Area of base .

so,

→ surface area of square pyramid = Area of 4 ∆'s + Area of square base .

→ surface area = 4[(1/2) * Base * height] + (side)²

→ surface area = 2(0.75 * 0.8) + (0.75)²

→ surface area = 2 * 0.6 + 0.5625

→ surface area = 1.2 + 0.5625

→ surface area = 1.7625 inches². (D) (Ans.)

Hence, the surface area of the figure is 1.7625 inches².