Question

The network shown in the figure is a part of a complete circuit. If at a certain instant, the current i is 4 A and is increasing at a rate of 104 A s–1, then (VP – VQ) will be

Answer 1

Answer:

76v

Explanation

Using KVL and eL  

 VP – 4 × 4 – 10 – 5 × 10–3 × 104– VQ = 0

VP – VQ­ = 76 V

Answer 2

Explanation:

$Resistance, \\ R = 1 Ω, emf , \\ ξ = 15V and \: inductance , \\ L = 5mH, di/dt = {10}^{3} A/s </p><p> \:$

vp-4×4-10-5×10-3×104-vq=0

vp-vq-76=0

vp-vq=76