THE NEUCLEOUS OF AN IRON ATOM HAS RADIOUS OF ABOUT 4.0×10m and contain 26 proton what is electrotrostatic repulsive force acts between two proton in such as a neucleous these are seperate by the distance of 1 radius
Answers
Answer:
Solution :
KEY IDEAS
The protons can be treated as charged particles, so the magnitude of the electrostatic force on one from the other is given by Coulomb.s law.
Calculation: Table 22-1 tells us that the charge of a proton is +e. Thus, Eq. 22-4 gives us
F=14πε0e2r2
=(8.99×109N⋅m2/C2)(1.602×1019C)2(4.0×10−5m)2
=14N. (Answer)
No explosion: This is a small force to be acting on a macroscopic object like a cantaloupe, but an enormous force to be acting on a proton. Such forces should explode the nucleus of any element but hydrogen (which has only one proton in its nucleus). However, they don.t not even in nuclei witha great many protons. Therefore, there must be some enormous attractive force to counter this enormous repulsive electrostatic force.