The new COVID-19 testing facility in Lucena City is operating with two laboratory
technicians. Technician A takes 2 hours to finish 50 samples of specimens from
CoVID-19 patients. Technician B takes 3 hours to finish 45 samples of specimens
from COVID-19 patients. Working together, how long should it take them to finish
150 samples of specimens from COVID-19 patients?
Hint:
Think about how many samples of specimens each technician can finish in one hour.
This is their testing rate
Answers
Given :-
- Technician A takes 2 hours to finish 50 samples of specimens from COVID-19 patients.
- Technician B takes 3 hours to finish 45 samples of specimens from COVID-19 patients.
To Find :-
- Working together, how long should it take them to finish 150 samples of specimens from COVID-19 patients ?
Solution :-
from given data we have,
→ Technician A finish samples in 2 hours = 50
So,
→ Technician A finish samples in 1 hours = (50/2) = 25 sample .
we can conclude that,
→ Efficiency of Technician A to finish samples is = 25 samples / hour.
Similarly,
→ Technician B finish samples in 3 hours = 45
So,
→ Technician B finish samples in 1 hours = (45/3) = 15 sample .
we can conclude that,
→ Efficiency of Technician B to finish samples is = 15 samples / hour.
Therefore,
→ Efficiency of (Technician A + Technician B) = 25 + 15 = 40 samples / hour.
Now, we need to find , working together, how long should it take them to finish 150 samples .
Hence,
→ Required Time = (Total samples to finish) / (Efficiency of A + B) = (150 / 40) = (15/4) = 3(3/4) = 3 + (3/4 * 60) = 3 hours 45 minutes. (Ans.)
∴ Technician A and Technician B together finish 150 samples in 3 hours 45 minutes.
Learn more :-
Giri does 2/5 piece of work in 10 days. Ankit does 5/9 of the remaining work in 15 days and Gaurav finishes remaining wo...
https://brainly.in/question/21025557
Answer:
3hours ad 45 minutes
Step-by-step explanation:
Required Time = (Total sample to finish)= ( Efficiency of A+B) = (150/40)=(15/4) =3(3/4)=3+(3/4*60)= 3hrs and 45 minutes