Question

the next to terms of the A.p :2k +1 ,3k+ 2,4k +3 a) 5k+4 and 6k + 5 b) AK+4and 4k +5 c)5k and 6k +5 c)5k and 6k​

Answer 1

Answer:

a) 5k + 4 and 6k + 5

Step-by-step explanation:

AP --> 2k +1 ,3k+ 2,4k +3

common difference = t2 - t1

                               = 3k + 2 - (2k+1)

                               =k + 1

t4 = t3 + d

   = 4k + 3 +(k+1)

   = 5k + 4

t5 = t4 + d

   = 5k + 4 + (k+1)

   = 6k + 5