The ninth term of A.P. is equal to seven times the second term and twelfth term exceeds five times the third term by 2. Find the a and d???
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9th term can be written as a +8d... where a is the first term and d the common difference...
and 3rd term = a +2d and so on
so given is
T9= 12.T2
T12 = 5.T3 + 2...
a+8d = 12a + 12d
11a= -4d
a = -4/11d ...
now from 2nd relation....
a + 11d = 5a + 10d + 2 ...
put the value of a and u'll get value of d... now go back and place that value of d ...and get the value of s
and 3rd term = a +2d and so on
so given is
T9= 12.T2
T12 = 5.T3 + 2...
a+8d = 12a + 12d
11a= -4d
a = -4/11d ...
now from 2nd relation....
a + 11d = 5a + 10d + 2 ...
put the value of a and u'll get value of d... now go back and place that value of d ...and get the value of s
AvX6677:
i mean D
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