Question

the ninth term of an A.p is equal to Sevan times the second term and the common difference​

Answer 1

The ninth term of an AP is equal to seven times the second term. Twelfth term exceeds five times the third term by 2. a = ?? and d = ?? Let the first term of A.P. be a and common difference be d.

Answer 2

Answer:

given,

a(9)=7×a(2)

a+8d=7×a+d

a+8d=7a+7d

8d-7d=7a-a

d=6a

hope it helps..