The ninth term of an A.P. is equal to the seventh times the second term and the twelfth term exceeds five times the third term by 2. Find the first term and the common difference?
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Answer:
Let the first term of A.P. be 'a' and the common difference be 'd'
Given,
a₉ = 7a₂
or, a+8d = 7(a+d) ________(i)
and
a₁₂ = 5a₃ + 2
or, a+11d = 5(a+2d) + 2 ________(ii)
from eq. (i)
a+8d = 7a+7d
-6a + d = 0 ________(iii)
from eq. (ii)
a+11d = 5a+10d + 2
-4a + d = 0 ________(iv)
Substracting eq. (iv) from eq. (iii), we get,
-2a = 2
a = 1
or,
from eq. (iii)
-6a + d = 0
d = 6
Hence,
First term is 1
Common difference is 6
Answered by
70
Answer :
- First term, a = 1
- Common difference, d = 6
Solution :
Given :
- The ninth term of an A.P. is equal to the seven times the second term.
- The twelfth term exceeds five times the third term by 2.
To Find :
- First term (a).
- Common difference (d).
Let's solve,
It is given that ,
- 9th term is 7 times the second term.
So,
It can be also written as :
Solving (i) ,
━━━━━━━━━━━━
- 12th term exceeds 5 times the 3rd term by 2.
So,
It can be also written as :
Solving (iii) ,
• d=6a ……(ii)
• d = 4a+2 ……(iv)
• d = 6a
Hence,
First term(a) is 1 and Common difference(d) is 6.
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