The ninth term of an AP is equal to seven times the second term and twelfth term exceeds five times the third term by 2. Find the first term and the common difference.
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9 term=a+8d
2 term=a+d
a/C into problem
a+8d=7(a+d)
a+8d=7a+7d
d= 6a...........(1)
12 term=a+11d
3 term=a+2d
a/C into problem
a+11d=5(a+2d/2)
a+11d=5a/2+10d/2
11d-5d=5a/2-a
6d=3a/2
d=1/4a..............(2)
from 1 and 2
6a=1/4a
a=0
d=0
I think help you above answer pls check question once
2 term=a+d
a/C into problem
a+8d=7(a+d)
a+8d=7a+7d
d= 6a...........(1)
12 term=a+11d
3 term=a+2d
a/C into problem
a+11d=5(a+2d/2)
a+11d=5a/2+10d/2
11d-5d=5a/2-a
6d=3a/2
d=1/4a..............(2)
from 1 and 2
6a=1/4a
a=0
d=0
I think help you above answer pls check question once
Anonymous:
Hey by 2 in the question means +2 not /2 so plz correct your answer
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