the no.consists of two digits.when it is divided by the sum of its digits,the quotient is 6 with no remainder. when the number is diminished by 9, the digits are reversed.Find the number
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Let the number be xy
When it is divided by the sum of its digits,the quotient is 6 with no remainder:
(10x + y)/(x+y) = 6
10x + y = 6x + 6y
4x = 5y
x = 5/4 y -------- (i)
When the number is diminished by 9, the digits are reversed:
10x + y - 9 = 10y + x
9x - 9y = 9
x - y = 1 ------ (ii)
Solving (i) and (ii) simultaneously;
x - y = 1
but, x = 5/4 y
So,
5/4 y - y = 1
y/4 = 1
y = 4
x = 5/4 y
x = 5/4 (4) = 5
So, the number = 54
When it is divided by the sum of its digits,the quotient is 6 with no remainder:
(10x + y)/(x+y) = 6
10x + y = 6x + 6y
4x = 5y
x = 5/4 y -------- (i)
When the number is diminished by 9, the digits are reversed:
10x + y - 9 = 10y + x
9x - 9y = 9
x - y = 1 ------ (ii)
Solving (i) and (ii) simultaneously;
x - y = 1
but, x = 5/4 y
So,
5/4 y - y = 1
y/4 = 1
y = 4
x = 5/4 y
x = 5/4 (4) = 5
So, the number = 54
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