Question

the no glucose molecules present in 10 ml of decimolar solution is

Answer 1

M = n/V

n = MV

n = 0.1 * 10 * 10^-3

n = 10^-3 mol

Number of molecules = 10^-3 * 6 * 10^23 = 6 * 10^20

Answer 2

Answer:

Explanation:

A decimolar solution is a O.1 Molar solution,

which has 0.1 moles glucose in a liter of solution

aka. 0.1 moles glucose in a 1000 ml of solution

? moles glucose = (10 ml) (0.1 mol / 1000 ml)

your answer, rounded to 1 sig fig is

0.001 moles of Glucose

all I see is one sig fig showing in "10ml" & in "decimolar